Matco Posted February 14, 2020 Report Share Posted February 14, 2020 (edited) Hi guys, I was looking the code of the 3.3.5 branch, and something got my attention, I will explain the case below. If I (a Player) teleport to a diff map than mine (I mean diff mapId, wiht command or something else), I will call TeleportTo, then Map* oldmap = IsInWorld() ? GetMap() : nullptr; oldmap will return something because at that point, I was already in a map, and GetMap can't return null because of ASSERT and I'm in a world too, then oldmap will do this oldmap->RemovePlayerFromMap(this, false); in the part of UpdateObjectVisibility(true) it will call Player::UpdateVisibilityForPlayer() at somepoint, then it will call VisibleNotifier with all G and W objects, and again Player::UpdateVisibilityOf ... now here is where I got lost, let's said I call a T = Creature if (HaveAtClient(target)) // in this case it will return true, it's an object that's in my client then if (!CanSeeOrDetect(target, false, true)) It should return false, because i'm changing world, so the Creature can be removed from my client vision, but where is that check, if I look into it, I got this bool WorldObject::CanSeeOrDetect(WorldObject const* obj, bool ignoreStealth, bool distanceCheck, bool checkAlert) const { if (this == obj) return true; // IsNeverVisible will return false || CanNeverSee will return false, because they are in the same GetMap() and same phase, since it doesn't change for a movement of worlds if (obj->IsNeverVisible() || CanNeverSee(obj)) return false; // those 2 will return false if (obj->IsAlwaysVisibleFor(this) || CanAlwaysSee(obj)) return true; // etc... } Then some checks of distance or ghost and dead stuff, but, doesn't it return false at the beginning like if (!IsInWorld()) return false; or where it does something like that? Because I got it returning true when should be false Edited February 14, 2020 by Matco Link to comment Share on other sites More sharing options...
Recommended Posts